1. Obtaining Properties of Sinusoidal Waves from Wave Function.
The sound produced by a speaker is given by the following pressure difference wave in air.
\begin{equation*}
\Delta p = (10 \text{ Pa})\, \cos(k x + 6000\, t + \pi),
\end{equation*}
where \(x\) is in meters and \(t\) in seconds and \(\Delta p(x,t)\) is the difference in atmospheric pressure from the ambient pressure at location \(x\) at time \(t\text{.}\) Suppose speed of this wave is \(343\text{ m/s}\) and density of air to be \(1.2\, \text{kg/m}^3\text{.}\)
(a) Angular frequency,
(b) Frequency,
(c) Wavenumber and Wavelength,
(d) Amplitude of the wave,
(e) The direction the wave is traveling,
(f) Bulk modulus of air,
(l) What is the corresponding particle displacement wave?
Answer.
Solution 1. a-k
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Angular frequency, \(\omega = 6000\, \text{rad/s}\text{.}\)
-
Frequency, \(f = \omega/2\pi = 955\, \text{Hz}\text{.}\)
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Wavelength, \(\lambda = v/f = 343 / 955 = 0.359\,\text{m}\text{.}\)Wavenumber, \(k = \frac{2\pi}{\lambda} = 17.5\,\text{m}^{-1}\text{.}\)
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Amplitude of the wave, \(A = 10\,\text{Pa}\text{.}\)
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The direction the wave is traveling: Negative \(x\)-axis since the \(x\) and \(t\) terms in the argument have the same sign.
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Bulk modulus of air \(B\) is obtained from \(v = \sqrt{B/\rho}\) with \(\rho\) the density of air. This gives \(B = \rho v^2 = 0.14\, \text{MPa}\text{.}\)
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Pressure differential at \(x=0\text{,}\) \(t = 1/5000\) sec: \(\Delta p = - 3.63\,\text{Pa}\text{.}\)
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Plot the pressure differential at \(x=0\) versus \(t\text{:}\) left as an exercise for student to complete.
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Plot the pressure differential at \(t=0\) versus \(x\text{:}\) left as an exercise for student to complete.
Solution 2. l
The phase of the dsplacment will have additional \(+\pi/2\) constant and the amplitude will be
\begin{equation*}
D_0 = \frac{P_0}{k B} = 4.1\times 10^{-6}\,\text{m} = 4.1\,\mu\text{m}.
\end{equation*}
Hence, the particle displacement wave with this sound wave is \((4\ \mu\text{m})\cos(17.5 x+ 6000 t + 3\pi/2)\text{.}\)



